Question

Даю 20б помогите алгебра

Answer 1

a) 2x^2-18=0 a) 3x^2-12=0
2x^2=18 3x^2=12
x^2=18/2 x^2=12/3
x^2=9 x^2= 4
x=+-3 x=+-2

б) x^2+2x=0 б)x^2-3x=0
x(x+2)=0 x(x-3)=0
x1=0 или x+2=0 x1=0 или x-3=0
x2=-2 x2=3

в) 4x^2=0. в) -7х^2=0
x^2=0/4. х^2=0/7
х=0. х=0