Question

log2(log4(log3(2x-1)))=log2(1/2)

Answer 1

ОДЗ:
1) log₄(log₃(2x-1) > 0
log₃(2x-1) > 1
2x - 1 > 3
x > 2
2) log₃(2x-1) > 0
2x - 1 > 1
x > 1
3) 2x - 1 > 0
x > 0,5
Пересечение x > 2

log₂(log₄(log₃(2x - 1))) = log₂(½)
log₄(log₃(2x - 1)) = ½
log₃(2x - 1) = 2
2x - 1 = 9
x = 5

Ответ: 5

Answer 2

ОДЗ :
log4(log3(2x-1))>0
log3(2x-1)>1
2x-1>3
2x>4
x>2

Answer 3

тогда простите...

Answer 4

дополните ответ

Answer 5

всё?

Answer 6

всё!

Answer 7

окей:)