Question

log2 56+4 log4 12-log2 63

Answer 1

$log_{2}56 + 4 log_{4}12 - log_{2}63 = log_{2}56 + 4 log_{ {2}^{2} }12 - log_{2}63 = log_{2}56 + 4 times frac{1}{2} log_{2}12 - log_{2}63 = log_{2}56 + 2 log_{2}12 - log_{2}63 = log_{2}56 + log_{2}144 - log_{2}63 = log_{2} frac{56 times 144}{63} = log_{2}128 = 7$
Ответ: 7