Question

Cos^2x+0,1cosx=0
Помогите решать уравнение

Answer 1

${cos}^{2} x + 0.1cosx = 0 \ cosx(cosx + 0.1) = 0 \ \ cosx = 0 \ x = frac{pi}{2} + pi n \ \ cosx + 0.1 = 0 \ cosx = - 0.1 \ x = + - arccos( - 0.1) + 2pi n \ x = + - (pi - arccos0.1) + 2pi n$
Ответ: pi/2 + pi*n, n € Z; +- (pi - arccos0,1) + 2pi*n, n € Z.