Question

Решите уравнение x3+3x2-8x-24=0

(3-2x)(2/7x-4)=0

Answer 1

1)x3+3x2-8x-24=0

х2(х+3)-8(х+3)=0

(х+3)(х2-8)=0

х+3=0          х2-8=0

х=-3            х= +√8  х=-√8

2)(3-2x)(2/7x-4)=0

3-2х=0     2/7х-4=0

х=3/2     х=4*7/2=14