Question

ПОМОГИТЕ ПОЖАЛУЙСТА
(6с-4)^2-(4с+3)^2=0

Answer 1

(6c - 4)² - (4c + 3)² = 0
(6c - 4 - (4c + 3))(6c - 4 + (4c + 3)) = 0
(6c - 4 - 4c - 3)(6c - 4 + 4c + 3) = 0
(2c - 7)(10c - 1) = 0

1) 2c - 7 = 0
2c = 7
c = 7/2 = 3,5

2) 10c - 1 = 0
10c = 1
c = 1/10 = 0,1

Ответ: 0,1 ; 3,5