Question

Решите систему неравенств
1>3z
4z-1>0

Answer 1

$3z-1<0; z-frac{1}{3}<0; z<frac{1}{3}$

$4z-1>0; z-frac{1}{4}>0; z>frac{1}{4}$

$frac{1}{4}<z<frac{1}{3}$