Question

Помогите решить:

1,5x^2+4x+2,5=0

Answer 1

$1,5x^2+4x+2,5=0; |cdot 2\\3x^2+8x+5=0\\D=4; ,; ; x_1=frac{-8-2}{6}= frac{-10}{6}=-frac{5}{3}=-1frac{2}{3}; ,; ; x_2=frac{-8+2}{6}=-1$