Question

помогите решить (°°°°°°°°°°°°°°°°°)

Answer 1

$displaystyle ttfrac{m}{m-3}+frac{3m}{(3-m)^{2}}=frac{3m}{(3-m)^{2}}-frac{m}{3-m}=frac{3m-m(3-m)}{(3-m)^{2}}=\\\=frac{m^{2}}{(3-m)^{2}}=bigg(frac{m}{3-m}bigg)^{2}$