Question

Преобразуйте в множители:
3а-3б-а^2+б^2;
m^3-n^2-nm^2+m^2

Answer 1

$3a - 3b - {a}^{2} + {b}^{2} =( 3a -3 b) - ( {a}^{2} - {b}^{2} ) = 3(a - b) - (a - b)(a + b) = (a - b)(3 - a - b)$
${m}^{3} - {n}^{2} - n {m}^{2} + {m}^{2} = ({m}^{3} - n {m}^{2}) + ( {m}^{2} - {n}^{2} ) = {m}^{2} (m - n) + (m - n)(m + n) = (m - n) ({m}^{2} + m + n)$