Question

(sin220°*cos8°+cos158°*cos98°)/(sin23°*cos7°+cos157°*cos97°)

Answer 1

Если не 220 а 202, то решается хорошо.
$frac{cos202cos8+cos158cos98}{sin23cos7+cos157cos97}$=
=$frac{cos(180+22)cos8+cos(180-22)cos(90+8)}{sin23cos7+cos(180-23)cos(90+7)}$=
$= frac{-sin22cos8+cos22sin8}{sin23cos7+cos23sin7}=$
$= frac{-sin14}{sin30}=-2sin14$