Question

(х+1) ВО 2 СТЕПЕНИ+2х(4х-1)

Answer 1

${(x + 1)}^{2} + 2x(4x - 1) = {x}^{2} + 2x + 1 + 8 {x}^{2} - 2x = 9 {x}^{2} + 1$

Answer 2

${x}^{2} + 2x + 1 + 8 {x}^{2} - 2x = 9 {x}^{2} + 1$