Question

помогите решить
(0.2х-10у)²

Answer 1

$(0.2x - 10y) {}^{2} \ \ ( frac{1}{5} x - 10y) {}^{2} \ \ ( frac{1}{5} x) {}^{2} - 2 frac{1}{5} x times 10y + (10y) { }^{2} \ \ frac{1}{25} x {}^{2} - 2 frac{1}{5} x times 10 + (10y) {}^{2} \ \ frac{1}{25} x {}^{2} - 4xy + (10y) {}^{2} \ \ frac{1}{25} x { }^{2} - 4xy + 100y {}^{2}$

Answer 2

спасибо