Question

решите пожалуйста прошу срочно

Answer 1

а) $(frac{a-b}{a^{2} + ab} -frac{a}{ab+b^{2}}) : (frac{1}{a+b} - frac{b^{2}}{ab^{2}-a^{3}}) =$$(frac{a-b}{a^{2} + ab} -frac{a}{ab+b^{2}}) : (frac{1}{a+b} - frac{b^{2}}{ab^{2}-a^{3}}) =  </p><p>\(frac{a-b}{a(a+b)} -frac{a}{b(a+b)}) : (frac{1}{a+b} - frac{b^{2}}{a(b^{2}-a^{2})}) =   </p><p>\(frac{b(a-b)}{ab(a+b)} -frac{a^{2}}{ab(a+b)}) : (frac{1}{a+b} - frac{b^{2}}{a(b-a)(b+a)}) =   </p><p>\ frac{ba-b^{2}-a^{2}}{ab(a+b)} : (frac{a(b-a)}{a(b-a)(b+a)} - frac{b^{2}}{a(b-a)(b+a)}) =   </p><p>\ frac{-a^{2}+ba-b^{2}}{ab(a+b)} : frac{a(b-a)-b^{2}}{a(b-a)(b+a)} =$

$frac{-a^{2}+ba-b^{2}}{ab(a+b)} : frac{ab-a^{2}-b^{2}}{a(b-a)(b+a)} =  </p><p>\ frac{-a^{2}+ba-b^{2}}{ab(a+b)} : frac{-a^{2}+ab-b^{2}}{a(b-a)(b+a)} =  </p><p>\ frac{-a^{2}+ba-b^{2}}{ab(a+b)} * frac{a(b-a)(b+a)}{-a^{2}+ab-b^{2}} = frac{b-a}{b}$

2)$(frac{2ab}{a^{2}-b^{2}} + frac{a-b}{2(a+b)})*frac{2a}{a+b}-frac{b}{a-b} =  \ (frac{2ab}{(a-b)(a+b)} + frac{a-b}{2(a+b)})*frac{2a}{a+b}-frac{b}{a-b} =  \ (frac{4ab}{2(a-b)(a+b)} + frac{(a-b)^{2}}{2(a+b)(a-b)})*frac{2a}{a+b}-frac{b}{a-b} =  \ frac{4ab+(a-b)^{2}}{2(a-b)(a+b)}*frac{2a}{a+b}-frac{b}{a-b} =  \ frac{4ab+a^{2}-2ab+b^{2}}{2(a-b)(a+b)}*frac{2a}{a+b}-frac{b}{a-b} =  \ frac{a^{2}+2ab+b^{2}}{2(a-b)(a+b)}*frac{2a}{a+b}-frac{b}{a-b} =$

$frac{a^{2}+2ab+b^{2}}{2(a-b)(a+b)}*frac{2a}{a+b}-frac{b}{a-b} =  \ frac{(a+b)^{2}}{2(a-b)(a+b)}*frac{2a}{a+b}-frac{b}{a-b} =  \ frac{a}{a-b}-frac{b}{a-b} =  \ frac{a-b}{a-b} = 1$