Question

система
3(2x-y)+5=-2(x+3y)+4
6(y+1)-1=5(2x-1)+8

Answer 1

{3(2х-у)+5=-2(х+3у)+4

{6(у+1)-1=5(2х-1)+8

{6х-3у+5=-2х-6у+4

{6х+6у-1=10х-5+8

{6х-3у+2х+6у=4-5

{6х+6у-10х=-5+8+1

{8х+3у=-1|*2

{-4х+6у=4

{16х+6у=-2

-

{-4х+6у=4

16х+6у-(-4х)-6у=-2-4

20х=-6|:20

х=-0,3=(-3/10)

8х+3у=-1

8*(-0,3)+3у=-1

-2,4+3у=-1

3у=-1+2,4

3у=1,4|:3

у=(14/30)

Ответ: ((-3/10);(14/30))