Question

5y^4+2y^2-3=0 помогите

Answer 1

5y^4 + 2y^2 - 3 = 0

5t^2 +2t-3=0

t=3/5
t=-1

y^2=3/5
y^2=-1

y=√15/5
y=-√15/5

y1=-√15/5
y2=√15/5

Answer 2

5у⁴+2у²-3=0
у²=а>0

5а²+2а-3=0
Д=4+60=64=8²

а=(-2±8)/10
а1=-1;а2=6/10=3/5

у²=-1;у€∅
у²=3/5
у=±√(3/5)=±√15/5