Question

Надо решить це способом введения новой переменной.

Answer 1

$( {x}^{2} + 2x - 3)( {x}^{2} + 2x + 2) = - 4 \ {x}^{2} + 2x = t \ (t - 3)(t + 2) = - 4 \ {t}^{2} - 3t + 2t - 6 + 4 = 0 \ {t}^{2} - t - 2 = 0 \ d = {b}^{2} - 4ac = 1 - 4 times ( - 2) = 9 \ t1 = frac{1 + 3}{2} = 2 \ t2 = frac{1 - 3}{2} = - 1 \ 1) : {x}^{2} + 2x = 2 \ {x}^{2} + 2x - 2 = 0 \ d = {b}^{2} - 4ac = 4 - 4 times ( - 2) = 4 + 8 = 12 \ x1 = frac{ - 2 + 2 sqrt{3} }{2} = - 1 + sqrt{3} \ x2 = frac{ - 2 - 2sqrt{3} }{2} = - 1 - sqrt{3} \ 2) : {x}^{2} + 2x = - 1 \ {x}^{2} + 2x + 1 = 0 \ {(x + 1)}^{2} = 0 \ x + 1 = 0 \ x = - 1$

Answer 2

Да хранит тебя карась