Question

$2^{x^{2} -3x+8} =64$

Answer 1

${2}^{ {x}^{2} - 3x + 8 } = 64 \ {2}^{ {x}^{2} - 3x + 8} = {2}^{6} \ {x}^{2} - 3x + 8 = 6 \ {x}^{2} - 3x + 2 = 0 \ d = {b}^{2} - 4ac = 9 - 4 times 2 = 1 \ x1 = frac{3 + 1}{2} = frac{4}{2} = 2 \ x2 = frac{3 - 1}{2} = frac{2}{2} = 1$
Ответ: 1; 2.

Answer 2

I hope this helps you