Ответы
Ответ дал:
0
Ответ дал:
0
ж
![frac{{x}^{3} - x}{x - {x}^{2} } = frac{x( {x}^{2} - 1) }{ - x(x - 1)} = \ = - frac{x(x - 1)(x + 1)}{x(x - 1)} = \ = - (x + 1) = - x - 1 frac{{x}^{3} - x}{x - {x}^{2} } = frac{x( {x}^{2} - 1) }{ - x(x - 1)} = \ = - frac{x(x - 1)(x + 1)}{x(x - 1)} = \ = - (x + 1) = - x - 1](https://tex.z-dn.net/?f=+frac%7B%7Bx%7D%5E%7B3%7D+-+x%7D%7Bx+-+%7Bx%7D%5E%7B2%7D+%7D+%3D+frac%7Bx%28+%7Bx%7D%5E%7B2%7D+-+1%29+%7D%7B+-+x%28x+-+1%29%7D+%3D+%5C+%3D+-+frac%7Bx%28x+-+1%29%28x+%2B+1%29%7D%7Bx%28x+-+1%29%7D+%3D+%5C+%3D+-+%28x+%2B+1%29+%3D+-+x+-+1)
з
![frac{ {a}^{2}x - a {x}^{2} }{ {x}^{2} - ax } = frac{ax(a - x)}{ - x(- x + a)} = - a frac{ {a}^{2}x - a {x}^{2} }{ {x}^{2} - ax } = frac{ax(a - x)}{ - x(- x + a)} = - a](https://tex.z-dn.net/?f=+frac%7B+%7Ba%7D%5E%7B2%7Dx+-+a+%7Bx%7D%5E%7B2%7D+%7D%7B+%7Bx%7D%5E%7B2%7D+-+ax+%7D+%3D+frac%7Bax%28a+-+x%29%7D%7B+-+x%28-+x+%2B+a%29%7D+%3D+-+a)
и
з
и
Вас заинтересует
1 год назад
8 лет назад
8 лет назад