Question

Помогите пожалуйста , номер 41 (ж , з , и ) 50 баллов

Answer 1

$displaystyle frac{x^3-x}{x-x^2}=frac{x(x^2-1)}{x(1-x)}=frac{x(x-1)(x+1)}{x(1-x)} =-(x+1)=-x-1\ \ \ frac{a^2x-ax^2}{x^2-ax}=frac{ax(a-x)}{x(x-a)}=-a\ \ \ frac{p^2-2pn+n^2}{n^2-pn}=frac{(p-n)^2}{n(n-p)}=frac{n-p}{n}$

Answer 2

ж
$frac{{x}^{3} - x}{x - {x}^{2} } = frac{x( {x}^{2} - 1) }{ - x(x - 1)} = \ = - frac{x(x - 1)(x + 1)}{x(x - 1)} = \ = - (x + 1) = - x - 1$
з
$frac{ {a}^{2}x - a {x}^{2} }{ {x}^{2} - ax } = frac{ax(a - x)}{ - x(- x + a)} = - a$
и
$frac{ {p}^{2} - 2pn + {n}^{2} }{ {n}^{2} - pn } = frac{ {n}^{2} - 2pn + {p}^{2} }{ {n}^{2} - pn } = \ = frac{(n - p) ^{2} }{ n( n - p)} = frac{( n - p)}{n}$