Question

Вычислите: ∫_(-1)^1▒(2x - 3x²)dx

Answer 1

2x^2/2-3x^3/3 | (-1;1) = x^2-x^3 | (-1;1) =1-1-(1+1)=0-2=-2

Answer 2

$intlimits^1_{-1} {(2x-3x^2)} , dx =(x^2-x^3)|_{-1}^1=1-1-1-1=-2$