Question

(1+3i/1+i)^2 срочно нужно

Answer 1

$Big (frac{1+3i}{1+i}Big )^2=Big (frac{(1+3i)(1-i)}{(1+i)(1-i)}Big )^2=Big (frac{1-i+3i-3i^2}{1-i^2}Big )^2=Big (frac{1+2i+3}{1+1}Big )^2=\\=Big (frac{4+2i}{2}Big )^2=(2+i)^2=2^2+2cdot 2cdot i+i^2=4+4i-1=3+4i$