Question

Z1=3-2i,Z2=-3+5i найти z1-z2, z1:z2, z1*z2

Answer 1

1) z1-z2=3-2i-(-3+5i)= 3-2i+3-5i=6-7i;

2) z1:z2=(3-2i)/-(3-5i)=-[(3-2i)×(3+5i)/(3-5i)×(3+5i)]=-[9+15i-6i-10i²/3²-(5i)²]=-[9+9i-10/9-25]=-(9i-1)/(-16)=(9i-1)/16;

3) z1×z2=(3-2i)×(5i-3)=15i-9-10i²+6i=21i-9-10=21i-19=-19+21i;