• Предмет: Математика
  • Автор: turkie
  • Вопрос задан 8 лет назад

Помогите a) b) c) d).

Приложения:

Ответы

Ответ дал: love67
0

а)1ц 1/5 * 1ц 2/3 * 1/7 + (1ц 1/7) ² = 6/5 * 5/3 * 1/7 + (8/7) ² = 2/7 + 64/49 = 14 / 49 + 64/49 =7849= 1 ц 29/49

б)(2ц 1/6 - 2/3) ² - 2ц 1/5 = ( 13/6 - 4/6) ² -11/5 = (3/2) ² - 11/5 =9/4 - 11/5 =45/20-44/20=1/20

с)10 - 2 * (3ц 1/5 - 2ц 1/4 * 1/3) = 10 - 2 * (16/5 - 9/4 * 1/3) = 10 - 2 * (16/5 - 3 / 4) =

= 10 - 32/5+6/4 =200/20 - 128/20+3020 =102/20=51/10= 5,1

д)(7/3 - 5/12 + 1ц 1/2): (2ц 3/4 - 5/6) = (73 - 5/12 + 3/2): (114 - 5/6) =(2812-512+18/12) :(33/12-10/12)=41/12*12/23=41/23 = 1ц 18/23



Ответ дал: Аноним
0
a) \ frac{6}{5} times frac{5}{3} times frac{1}{7} + ( frac{8}{7} ) {}^{2} = 2 times frac{1}{7} + frac{64}{49} = frac{2}{7} + frac{64}{49} = frac{78}{49} = 1 frac{29}{49} <br />\ \<br />b)\( frac{13}{6} - frac{2}{3} ) {}^{2} - frac{11}{5} = ( frac{3}{2} ) {}^{2} - frac{11}{5} = frac{9}{4} - frac{11}{5} = frac{1}{20} = 0.05 \ \ c) \ 10 - 2( frac{16}{5} - frac{9}{4} times frac{1}{3} ) = 10 - 2( frac{16}{5} - frac{3}{4} ) = 10 - 2 times frac{49}{20} = 10 - frac{49}{10} = frac{51}{10} = 5.1 \ \ d) \ ( frac{7}{3} - frac{5}{12} + frac{3}{2} ) div ( frac{11}{4} - frac{5}{6} ) = frac{41}{12} div frac{23}{12} = frac{41}{12} times frac{12}{23} = 41 times frac{1}{23} = frac{41}{23} = 1 frac{18}{23}
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