Question

Пж решите (6x-13)(7x-42)(0,26-0,12x)=0
Срочно надо

Answer 1

$(6x - 13)(7x - 42)(0.26 - 0.12x) = 0\ 1. \ 6x - 13 = 0 \ 6x = 13 \ x = 2 frac{1}{6} \ 2. \ 7x - 42 = 0 \ 7x = 42 \ x = 6 \ 3. \ 0.26 - 0.12x = 0 \ 0.12x = 0.26 \ x = frac{0.26}{0.12} = frac{26}{12} = frac{13}{6} = 2 frac{1}{6}$
Ответ: все три икса