Question

Сократите дроби:
1)8a^3 -b^3 /4a^2 -b^2
2)ab+ac /ab-3b+ac-3c

Answer 1

1)(8a³-b³)/(4a²-b²)=(2a-b)(4a²+2ab+b²)/(2a+b)(2a-b)=(4a²+2ab+b²)/(2a+b)

2)(ab+ac)/(ab-3b+ac-3c)=a(b+c)/(b(a-3)+c(a-3))=

=a(b+c)/(a-3)(b+c)=a/(a-3)