Question

x +y =6
x2- y=14
$x + y = 6 \ x2 - y = 14$

Answer 1

$x + y = 6 \ x {}^{2} - y = 14 \ \ {x}^{2} + x = 20 \ {x}^{2} + x - 20 = 0 \ d = {b}^{2} - 4ac = 1 + 80 = 81 \ x1 = frac{ - b + sqrt{d} }{2a} = frac{8}{2} = 4 \ x2 = frac{ - b - sqrt{d} }{2a} = frac{ - 10}{2} = - 5 \ y = 6 - x \ y1 = 2 \ y2 = 11$
Ответ: x1 = 4; y1 = 2; x2 = -5; y2 = 11