Question

Найдите предел функции Lim х->-3 х^2+5x+6/x^2+6x+9

Answer 1

$lim limits _{x - > - 3} frac{ {x}^{2} + 5x + 6}{ {x}^{2} + 6x + 9 } = { frac{0}{0} } = lim limits _{x - > - 3} frac{(x + 3)(x + 2)}{(x + 3 {)}^{2} } = lim limits _{x - > - 3} frac{x + 2}{x + 3 } = frac{ - 1}{0} = infty$

Answer 2

Спасибо большое)