Question

Решите задания, по математике, буду благодарна

Answer 1

Решение дано на фото.

Answer 2

проверьте третье, как минимум при подстановке не сходится

Answer 3

1) 2ˣ⁺² = 2⁶

x+2 = 6

x = 4

2) 2ˣ⁻²(4 + 2 + 1) =56

2ˣ⁻²*7 = 56

2ˣ⁻² = 8

2ˣ⁻² = 2³

x-2 = 3

x = 5

3) 2ˣ⁺³ = t > 0

t² + 16t = 17

(t + 17)(t - 1) = 0

t = 1

2ˣ⁺³ = 2⁰

x+3 = 0

x = -3

4) 2⁻ˣ < 2²

-x < 2

x > -2

5) 2⁻ˣ ≤ 2⁴

-x ≤ 4

x ≥ -4

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Answer 4

1) 2ˣ⁺² = 2⁶

x+2 = 6

x = 4

2) 2ˣ⁻²(4 + 2 + 1) =56

2ˣ⁻²*7 = 56

2ˣ⁻² = 8

2ˣ⁻² = 2³

x-2 = 3

x = 5

3) 2ˣ⁺³ = t > 0

t² + 16t = 17

(t + 17)(t - 1) = 0

t = 1

2ˣ⁺³ = 2⁰

x+3 = 0

x = -3

4) 2⁻ˣ < 2²

-x < 2

x > -2

5) 2⁻ˣ ≤ 2⁴

-x ≤ 4

x ≥ -4

Answer 5

1) 2ˣ⁺² = 2⁶

x+2 = 6

x = 4

2) 2ˣ⁻²(4 + 2 + 1) =56

2ˣ⁻²*7 = 56

2ˣ⁻² = 8

2ˣ⁻² = 2³

x-2 = 3

x = 5

3) 2ˣ⁺³ = t > 0

t² + 16t = 17

(t + 17)(t - 1) = 0

t = 1

2ˣ⁺³ = 2⁰

x+3 = 0

x = -3

4) 2⁻ˣ < 2²

-x < 2

x > -2

5) 2⁻ˣ ≤ 2⁴

-x ≤ 4

x ≥ -4

Подробнее - на Znanija.com - https://znanija.com/task/29675067#readmore