Question

СРОЧНО!!!Разложите на множители a2b4-c2d8

Answer 1

$tt a^2b^4-c^2d^8={(ab^2)}^2-{(cd^4)}^2=(ab^2-cd^4)(ab^2+cd^4)$

Answer 2

(Ab^2-cd^4)(ab^2+cd^4)