Question

упростите пожалуйста срочно...
2х*(8х-1) - (4х+1)^2=

4(3y-1)^2 - 18y(2y-1)=

Answer 1

$2x(8x - 1) - {(4x + 1)}^{2} = \ 16 {x}^{2} - 2x - 16 {x}^{2} - 8x - 1 = - 10x - 1$
$4{(3y - 1)}^{2} - 18y(2y - 1) = \ 4(9 {y}^{2} - 6y + 1) - 36 {y}^{2} + 18y = \ 36 {y}^{2} - 24y + 4 - 36 {y}^{2} + 18y = 4 - 6y$