Question

Только левый столбик

Answer 1

$1); ; (x-1)(x+9)<0qquad +++(-9)---(1)+++\\xin (-9,1)\\2); ; x^2>9; ,; ; (x-3)(x+3)>0; ,\\+++(-3)---(3)+++qquad xin (-infty ,-3)cup (3,+infty )\\3); ; frac{x(x-1)}{3-x}leq 0; ,; ; frac{x(x-1)}{-(x-3)}leq 0; ,; ; frac{x(x-1)}{x-3}geq 0\\---[, 0, ]+++[, 1, ]---(3)+++qquad xin [, 0,1, ]cup (3,+infty )\\4); ; x^2(5x-4)(x+7)<0; ,\\+++(-7)---(0)---(4/5)+++\\xin (-7,0)cup (0,frac{4}{5})$

$5); ; y=sqrt{frac{-3x+x^2-4}{9-x^2}}; ; ,; ; OOF:; ; left { {{frac{-3x+x^2-4}{9-x^2}geq 0} atop {9-x^2ne 0}} right. \\x^2-3x-4=0; ; to ; ; x_1=-1; ,; x_2=4; ; (teorema; Vieta)\\9-x^2ne 0; to ; ; x^2ne 9; ,; ; xne pm 3\\frac{x^2-3x-4}{-(x^2-9)}geq 0; ; ,; ; frac{(x+1)(x-4)}{(x-3)(x+3)}leq 0; ; ,\\+++(-3)---[, -1, ]+++(3)---[, 4, ]+++\\xin (-3,-1, ]cup (3,4, ]$