Question

Как решить:
2+3i/5-2i
i-1/i+1

Answer 1

=(2+3i)(5+2i)/(5-2i)(5+2i)=

(10+4i+15i+6i²)/(25-4i²)=

(4+19i)/29

2)=(i-1)(i-1)/(i+1)(i-1)=(i²-i-i+1)/(i²-1)=2i/2=i


(i²=-1)