Question

[16^x] -6*[4^x]+5=0
........

Answer 1

пусть 4^x= t,  t>0

t²-6t+5=0

D= 36-20=16

t1= (6+4)/2= 5

t2= (6-4)/2= 1

1) 4^x=1

x1=0

2) 4^x=5

x2= log4(5)