Question

Ученикам 8 класса ВОПРОС 8

Answer 1

=
$frac{81x {}^{2} }{9(9x {}^{2} - 1) } + frac{54x}{3(3x - 1) times 3(3x + 1)} + frac{9}{9(9x {}^{2} - 1)} = frac{9x {}^{2} }{9x {}^{2} - 1) } + frac{6x}{(3x - 1)(3x + 1)} + frac{1}{9x {}^{2} - 1 } = frac{9x {}^{2} + 6x + 1}{9x - 1} = frac{(3x +1) {}^{2} }{(3x - 1)(3x + 1)} = frac{3x + 1}{3x - 1}$вместо t там x