Question

помогите пожалуйста!!!!! 2.11 и 2.12

Answer 1

$2.11 \ 1) = (0.1 {a}^{3} {b}^{2} )^{2} \ 2) = (3 {b}^{2} {c}^{4} )^{2} \ 3) = (10p {q}^{3} )^{2} \ \ 2.12 \ 1) = (4 {a}^{3} )^{3} \ 2) = (0.1 {x}^{4} ) {}^{3} \ 3) = ( - frac{3}{2} {c}^{5} ) {}^{3} \ 4) = ( - 3 {a}^{2} {y}^{3} ) {}^{3} \ 5) = (10a {b}^{2} ) {}^{3} \ 6) = (0.2 {b}^{2} {y}^{3} ) {}^{3}$