Question

Помогите пожалуйста

Answer 1

$frac{9a^{3}b^{7}c^{3}}{27a^{2}b^{9}c^{3}}=frac{a}{3b^{2}}\frac{5-a}{x-y}-frac{5+a}{y-x}=frac{5-a}{x-y}+frac{5+a}{x-y}=frac{5-a+5+a}{x-y}=frac{10}{x-y}\frac{2a-2}{x^{2}-y^{2}}*frac{y+x}{a-1} =frac{2(a-1)}{(x-y)(x+y)}*frac{y+x}{a-1}=frac{2}{x-y}}$

Answer 2

$frac{9a^{3}b^{7}c^{3}}{27a^{2}b^{9}c^{3}} =frac{a}{3b^{2} }$

$frac{5-a}{x-y} - frac{5+a}{y-x}= frac{5-a}{x-y} + frac{5+a}{x-y}=frac{5-a+5+a}{x-y} =frac{10}{x-y}$

$frac{2a-2}{x^{2}-y^{2}} * frac{y+x}{a-1} = frac{2(a-1)}{(x-y)(x+y)} * frac{y+x}{a-1} = frac{2}{x-y}$