Question

Решить
x^2-3x+2/x^2+3x+2≥1

Answer 1

$frac{ {x}^{2} - 3x + 2 - {x}^{2} - 3x - 2 }{(x + 1)(x + 2)} geqslant0 \ - frac{6x}{(x + 1)(x + 2)} geqslant 0$
х=-2
х=-1
х=0
__+_-2__-_-1___+_0__-___
(-&;-2)(-1;0]