Question

4. Подробно. Спасибо. 50 б.

Answer 1

$displaystyle tt left(frac{2}{(1-x)^{2}}+frac{1}{x^{2}-1}right)cdot (x-1)^{2}-frac{3x}{x+1}=left(frac{2}{(1-x)^{2}}-frac{1}{1-x^{2}}right)cdot (1-x)^{2}-frac{3x}{1+x}=\\\=frac{2(1+x)-(1-x)}{(1-x)^{2}cdot (1+x)}cdot (1-x)^{2}-frac{3x}{1+x}=frac{3x+1-3x}{1+x}=frac{1}{1+x};\\\npu x=-1,5 frac{1}{1+x}=frac{1}{1-1,5}=-2;$