Question

алгебра срочно..........

Answer 1

$2x^2-8x+3=2left(x^2-4xright)+3=2left(x^2-2cdot2cdot x+2^2-2^2right)+3=\=2left(left(x-2right)^2-4right)+3=2left(x-2right)^2-8+3=2left(x-2right)^2-5$

$-3x^2+4x-1=-3left(x^2-dfrac{4}{3}xright)-1=\\=-3left(x^2-2cdotdfrac{2}{3}cdot x+left(dfrac{2}{3}right)^2-left(dfrac{2}{3}right)^2right)-1=\\=-3left(left(x-dfrac{2}{3}right)^2-dfrac{4}{9}right)-1=\\=-3left(x-dfrac{2}{3}right)^2+dfrac{4}{3}-1=-3left(x-dfrac{2}{3}right)^2+dfrac{1}{3}$

Answer 2

ептвоюмать