Question

Упростить
√27-2√3+3√75=
(2√5-√20)√5=
(3√3-4)в квадрате =
Прошу с полным решением

Answer 1

$sqrt{27}-2sqrt{3}+3sqrt{75}=sqrt{9*3}-2sqrt{3}+3sqrt{25*3}=3sqrt{3}-2sqrt{3}+5sqrt{3}=6sqrt{3}\(2sqrt{5}-sqrt{20})*sqrt{5}=(2sqrt{5}-sqrt{4*5})*sqrt{5}=(2sqrt{5}-2sqrt{5})*sqrt{5}=0*sqrt{5}=0\ (3sqrt{3}-4)^{2}=(3sqrt{3})^{2}-2*3sqrt{3}*4+4^{2}=27-24sqrt{3}+16=43-24sqrt{3}$

Answer 2

неверно*

Answer 3

:(