Question

помогите пожалуйста срочно зарание спасибо)!!!

Answer 1

Решение задания приложено

Answer 2

во 2м ошибочка : 1/27=3^(-3), а не 3^3.

Answer 3

Ок, спасибо.

Answer 4

$log_{ frac{1}{ sqrt{2} } }( frac{1}{8} ) = x \ log_{ frac{1}{ sqrt{2} } }( frac{1}{2} ) ^{3} = x \ x = log_{ frac{1}{ sqrt{2} } }( frac{1}{ sqrt{2} } ) ^{6} \ x = 6$
$log_{3 sqrt{3} }( frac{1}{27} ) = x \ x = log_{( sqrt{3}) ^{3} }(3) ^{ - 3} \ x = log_{( sqrt{3}) ^{3} }( sqrt{3}) ^{ - 6} \ x = frac{ - 6}{3} \ x = - 2$
$log_{x}(0.125) = - 3 \ log_{x}( {0.5}^{3} ) = - 3 \ 3 log_{x}(0.5) = - 3 \ log_{x}( frac{1}{2} ) = -1 \ x = 2$
$log_{x}(4) = - frac{1}{2} \ {x}^{ - frac{1}{2} } = 4 \ frac{1}{ sqrt{x} } = 4 \ x = frac{1}{16}$
$log_{16}(x) = frac{3}{4} \ x = {16}^{ frac{3}{4} } \ x = {2}^{4 times frac{3}{4} } \ x = {2}^{3} \ x = 8$
$log_{5}(x) = - 3 \ x = {5}^{ - 3} \ x = frac{1}{ {5}^{3} } \ x = frac{1}{125}$
$log_{6}(x) = - {2} \ x = {6}^{ - 2} \ x = frac{1}{36}$
$log_{x}(8) = - frac{1}{2} \ {x}^{ - frac{1}{2} } = 8 \ frac{1}{ sqrt{x} } = 8 \ x = frac{1}{64}$