Question

32^2/3 =
3^-4 =
log32 43 - 2log2 1 =

Answer 1

$32^{frac{2}{3} } =sqrt[3]{32^{2} } =sqrt[3]{1024} =8sqrt[3]{2} \ \ 3^{-4} =frac{1}{3^{4} } =frac{1}{81}$

㏒₃₂(43)-2㏒₂(1)=㏒₃₂(43)-2·0=㏒₃₂(43)-0=㏒₃₂(43)=㏒₂⁵(43)=(1/5)㏒₂(43)