Question

Пусть f(x)=x³, g(x)=x²+1. Найти :
1) f(x)+3g(x)+3x-2
2) g( f(x))

Answer 1

1) f(x)+3g(x)+3x-2=х³+3(х²+1)+3х-2=
=х³+3х²+3+3х-2=х³+3х²+3х+1.
2) g( f(x))=(х³)²+1=х^6+1.