Question

1 + 2(17-6x)/х2-6х+8 = 1-2х/х-4 - 11/х-2

Answer 1

$1+frac{2(17-6x)}{x^{2}-6x+8 } =frac{1-2x}{x-4}-frac{11}{x-2}\1+frac{34-12x}{(x-4)(x-2)}-frac{1-2x}{x-4}+frac{11}{x-2}=0\frac{x^{2}-6x+8+34-12x-x+2+2x^{2}-4x+11x-44}{(x-4)(x-2)}=0\frac{3x^{2}-12x }{(x-4)(x-2)}=0\frac{3(x^{2}-4x) }{(x-4)(x-2)}=0\x^{2}-4x=0,x-2neq0,x-4neq 0\x(x-4)=0,xneq2,xneq 4\x_{1}=0\x_{2}=4$- не уд.

Ответ : 0