Question

Решите уравнения 7(х-8)=3(х+6)+1
6(1+5х)=5(1+6х)
5(3х+1)=2(х-3)

Answer 1

1)
$7(x - 8) = 3(x + 6) + 1 \ 7x - 56 = 3x + 18 + 1 \ 7x - 3x = 19 + 56 \ 4x = 75 \ x = 75 div 4 \ x = 18.75$
2)
$6(1 + 5x) = 5(1 + 6x) \ 6 + 30x = 5 + 30x \ 30x - 30x = 5 - 6 \ 0 = - 1$
х € ∅

3)
$5(3x + 1) = 2(x - 3) \ 15x + 5 = 2x - 6 \ 15x - 2x = - 6 - 5 \ 13x = - 11 \ x = - frac{11}{13}$

Answer 2

7(х-8)=3(х+6)+1

7х-56=3х+18+1

7х-3х=56+18+1

4х=75

х=75/4

х=18,75

6(1+5х)=5(1+6х) - нет решения

5(3х+1) = 2(х-3)

15х+5=2х-6

13х=-11

х = - 11/13