Question

matematika 6 klass pri kakix naturalnix znacheniyax p drob 24 p budet naturalnix chislom

Answer 1

$q = frac{24}{p} \ p = 1 = > q = 24 \ p = 2 = > q = 12 \ p = 3 = > q = 8 \ p = 4 = > q = 6 \ p = 6 = > q = 4 \ p =8 = > q = 3 \ p = 12 = > q = 2 \ p = 24 = > q = 1$