Question

Решите уравнение:
1) $2^{x+3}=64$
2) $3^{frac{x}{2} } =27$

Answer 1

1.
${2}^{x + 3} = 64$
${2}^{x + 3} = {2}^{6}$
$x + 3 = 6$
$x = 3$
2.
${3}^{ frac{x}{2} } = 27$
${3}^{ frac{x}{2} } = {3}^{3}$
$frac{x}{2} = 3$
$x = 6$