Question

Упростите выражение

2y^2 - 5xy/ x^2-4y^2 - x/2y - x - y/x+2y

y+12/8y+32 - y+4/8y-32 + 9/y^2 - 16

Answer 1

$frac{2y^2-5xy}{x^2-4y^2}-frac{x}{2y-x}-frac{y}{x+2y}=frac{2y^2-5xy}{(x-2y)(x+2y)}+frac{x}{x-2y}-frac{y}{x+2y}=frac{2y^2-5xy}{(x-2y)(x+2y)}+frac{x(x+2y)}{(x-2y)(x+2y)}-frac{y(x-2y)}{(x-2y)(x+2y)}=frac{2y^2-5xy+x^2+2xy+2y^2-xy}{(x-2y)(x+2y)}=frac{4y^2-4xy+x^2}{(x-2y)(x+2y)}=frac{(2y-x)^2}{-(2y-x)(x+2y)}=frac{2y-x}{-(x+2y)}=frac{x-2y}{x+2y}$

$frac{y+12}{8y+32}-frac{y+4}{8y-32}+frac{9}{y^2-16}=frac{y+12}{8(y+4)}-frac{y+4}{8(y-4)}+frac{9}{(y-4)(y+4)}=frac{(y+12)(y-4)}{8(y+4)(y-4)}-frac{(y+4)^2}{8(y-4)(y+4)}+frac{9*8}{8(y-4)(y+4)}=frac{y^2+8y-36-y^2-8y-16+72}{8(y+4)(y-4)}=frac{20}{8(y^2-16)}=frac{5}{2y^2-32}$