Question

98 баллов для умных СРОЧНО

Answer 1

$sqrt{asqrt[3]{a}}sqrt[3]{asqrt{a}}=a^{frac{1}{2}+frac{1}{6}+frac{1}{3}+frac{1}{6}}=asqrt{a}$

$sqrt[4]{bsqrt[3]{b^2}}sqrt[3]{b^2sqrt[4]{b}}=b^{frac{1}{4}+frac{2}{12}+frac{2}{3}+frac{1}{12}}=sqrt[6]{b^7}$

$sqrt[4]{frac{a}{b}sqrt{frac{a}{b}}}sqrt{frac{a}{b}sqrt[4]{frac{a}{b}}}=frac{a}{b}^{frac{1}{4}+frac{1}{8}+frac{1}{2}+frac{1}{8}}=frac{a}{b}$

$sqrt[3]{asqrt[3]{asqrt[3]{a}}}=a^{frac{1}{3}+frac{1}{9}+frac{1}{27}}=sqrt[27]{a^{13}}$