Question

(a+3)/(4a+4)-(a+1)/(4a-4)-a/(1-aa) помогите упростить

Answer 1

$frac{a+3}{4a+4}-frac{a+1}{4a-4}-frac{a}{1-a^2}=frac{a+3}{4(a+1)}-frac{a+1}{4(a-1)}+frac{a}{a^2-1}=frac{(a+3)(a-1)}{4(a+1)(a-1)}-frac{(a+1)(a+1)}{4(a-1)(a+1)}+frac{4a}{4(a^2-1)}=frac{a^2+2a-3-a^2-2a-1+4a}{4(a+1)(a-1)}=frac{4a-4}{(a+1)(4a-4)}=frac{1}{a+1}$